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Dreadnought Mass Accelerators- The math behind it


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#1
QueSera

QueSera
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 1J= 1kg*m^2/s^

1 Joule = 1 Kilogram * 1meter squared/ 1 second second squared

20 kg Weight
0.01 Light Speed

Speed of Light = 299,792,458m/s

xJ= 20kg* [(299,792,458*0.01)^2m *(1s)^2]

J= 20* [(2,997,924.58)^2 *(1)]
J= 20* 8987551787368.1764
J= 179,751,035,747,363.528

So the projectile fired by a Dreadnought is roughly 1.8x10^14 Joules of energy (1 Megaton = 4.18 petajoules which is 4.18x 10^15). 20kg at 1% the speed of light is roughly 0.41 Megatons or 410 kilotons.  Which is approximately 23 times the yield of the "Little boy" dropped on Hiroshima.


So pretty much once you get past the math, those dreadnoughts are damn powerful.
So Issac Newton really is the deadliest SOB in space.

#2
adam_grif

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I'm not entirely sure where you went wrong, but you did.



Everest class dreadnought fires a 20 KG slug @ 0.013C (aka 1.3% of lightspeed). This gives us 20 KG at 3,897,301.954 m/s, or a kinetic energy of 151,900,000,000,000 J (1.519E+14 Joules). A 1 KT explosion has 4.184E+12 joules, so you divide the first number by the second number, and it comes out at 36.3.



So the yield is 36.3 KT, slightly lower than the Codex stated figure of 38 KT. Your figure is off by 1 order of magnitude. You can hunt for the mistake yourself though, because I have stuff to do.