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Mass Effect Troll Science


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#1
ObserverStatus

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Inspired byt the troll science meme and some off mass effect's zanier codex entries, i can't believe noone has thought of this sooner!
Image IPB
Image IPB
post your own if you like

#2
Null_

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I thought this topic will be about "how 2 troll"

This is epic tho.

#3
AdmiralCheez

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Three-eyed trollface is priceless.

#4
Ryzaki

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Okay I laughed.

#5
Sentox6

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I've actually wondered when someone would do one of these. Kudos.

#6
Sereiphiel

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lol trolldad strikes once again!

#7
Guest_Imperium Alpha_*

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:police:The law like you troll science:police:

#8
ObserverStatus

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Null_ wrote...

I thought this topic will be about "how 2 troll"
This is epic tho.

What, like that "trolls are jerks" thread that got locked yesterday?

#9
Khan the Mad

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Momentum in Mass Effect is the same as in real life p = m*V. It works because momentum is conserved, and so is energy, so when you reduce the mass, the velocity increases. Which means that since the potential energy of the particle is reduced, you can afford the increase in kinetic energy, which is what is used to pierce the armor and kinetic barriers, not momentum. It is not exactly precise, but that's how it works, not by changing the formula of momentum.

EDIT: I made a quick calculation, and there is always an increase in total energy of the particle when the mass is reduced, and always a decrease when the mass is increased. I wonder where that energy comes from / goes to.

EDIT2: Actually, I was wrong. There can be an increase in energy when the mass is increased as well, depending on the starting energy values. Let me make another calculation to see if the reverse is possible for decrease in mass.

EDIT3: From what I can tell, it depends on the initial PE / KE ratio as well as the m0 / m1 ratio. I haven't been able to come up with the exact values where both momentum and energy are perfectly preserved, so I'll leave that up to someone else.

Modifié par Khan the Mad, 20 février 2011 - 03:32 .


#10
pacer90

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E = 1/2*mass*velocity-squared



P = v/m



So it's not a linear relationship it's an exponential one. A 1g bullet travelling at 3000m/s will hit with a lot less impact than a 0.1g bullet travelling at 9.2x10^23 m/s

#11
ObserverStatus

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Khan the Mad wrote...

Momentum in Mass Effect is the same as in real life p = m*V. It works because momentum is conserved, and so is energy, so when you reduce the mass, the velocity increases. Which means that since the potential energy of the particle is reduced, you can afford the increase in kinetic energy, which is what is used to pierce the armor and kinetic barriers, not momentum. It is not exactly precise, but that's how it works, not by changing the formula of momentum.

EDIT: I made a quick calculation, and there is always an increase in total energy of the particle when the mass is reduced, and always a decrease when the mass is increased. I wonder where that energy comes from / goes to.

EDIT2: Actually, I was wrong. There can be an increase in energy when the mass is increased as well, depending on the starting energy values. Let me make another calculation to see if the reverse is possible for decrease in mass.

EDIT3: From what I can tell, it depends on the initial PE / KE ratio as well as the m0 / m1 ratio. I haven't been able to come up with the exact values where both momentum and energy are perfectly preserved, so I'll leave that up to someone else.

But if that were the case, we would have to expect that ferrous slugs are brought to the ammount of force delivered by a nuclear bomb with magnetic coils alone, which seems unlikely.  Also, in the "Cerberus Daily News" that one Turian terrorist claims that he can destroy cities by hitting cities with spaceships at ftl speeds.