11 réponses à ce sujet

[Xardex]

I have a positive float with an unknown value. (User input)
I need to get the numbers after the dot as a integer.

examples:

00.65 -> 65
24.38 -> 38
98.00 -> 0


This is not nwscript related. (Its C++)

Any help appreciated.

Modifié par Xardex, 10 septembre 2011 - 04:00 .

[Shadooow]

Convert to string and take everything from dot right. Not sure how or if its possible to convert it into string or char though.

Modifié par ShaDoOoW, 10 septembre 2011 - 04:15 .

[Lightfoot8]

here is how I would do it in NWScript. Assuming that the number is inputed as a float to get the forst two decimals.

int Get2decimalsAsInt(float input)
{
input = (input- FloatToInt( input)) * 100;
return FloatToInt(input);
}

Hope that helps.

[Xardex]

I ended up using messing around with 'static_cast <newt type> (value)'

Thanks for the help anyway!

[Rolo Kipp]

<works through it on his fingers...>

Lightfoot8 wrote...
...
int Get2decimalsAsInt(float input)
{
input = (input- FloatToInt( input)) * 100;
return FloatToInt(input);
}
...

Nicely done :-)

<...and doesn't even need to take off his boots!>

[Shadooow]

Lightfoot: this really works? Thought it will round up the float again.

[Rolo Kipp]

<stepping on...>

ShaDoOoW wrote...

Lightfoot: this really works? Thought it will round up the float again.

It should work like this (assuming float input of yy.xxxx)
:
1) FloatToInt( input) evaluates as  yy.xxxxx -> int (yy)
2) (input- int( yy )) evaluates as (yy.xxxx - yy) -> float (.xxxxx)
3) (float (.xxxxx)) * 100 evaluates as (.xxxx)*100 -> float (xx.xx)
and therefore:
4) return FloatToInt(input); evaluates as return FloatToInt(xx.xx) -> return int (xx)

input = (input- FloatToInt( input)) * 100;
return FloatToInt(input);

Elegant, IMO :-)

<...the cat's toes>

[Lightfoot8]

ShaDoOoW wrote...

Lightfoot: this really works? Thought it will round up the float again.

I do not follow what you are saying.   FloatToInt  does not round.  

And I guess I lied when I said I would do it that way in NWScript.  I only did it that way because I do not know if C++ uses the operators the same way and I do not know if he wants the +\\- state of the original number preserved.  what I would use would look more like.

int Get2decimalsAsInt(float input)
{
   input = input * 100 ;
   return FloatToInt(input) % 100;
}

Modifié par Lightfoot8, 10 septembre 2011 - 07:19 .

[_six]

Going from ShaDoOoW's method, as Lightfoot's will only work with a set number of decimal places...

int decsAsInt(float val)
{
stringstream temp;
temp << val;
string Str1 = temp.str();

int pos = Str1.find('.');
Str1.replace(0, pos+1, "");

return atoi(Str1.c_str());
}

I hate wrestling with types in c++ too. There's probably a much nicer way to convert than using a stringstream, but if there is it's apparently a lot harder to remember

[Xardex]

I didn't say it but the input would only have a max of two decimals. I did it in a fashion similiar to Lightfoot's method, though his method would work too.

Modifié par Xardex, 11 septembre 2011 - 11:18 .

[Axe_Murderer]

fmod(x,1) *100

[Rolo Kipp]

<looks on...>

Axe_Murderer wrote...

fmod(x,1) *100

Sweet! :=)

<...with big eyes>