Okay let's say you've maxed overload, taking the chain option at both ranks 4 and 6 (what you picked at rank 5 is irrelevent for this). Assume no other bonuses or anything to make this simpler. This will result in three enemies being hit with overload. My question is about how the damage works.
Enemy one is pretty straightforward. Rank 3 gives 20% damage increase, rank 6 provides 15% damage increase. First enemy is hit with 135% damage.
Second enemy is where I start to be unsure. The chains state that it will hit an additional target with 60% reduced damage. Does this simply get subtracted the same way damage bonus percentages get added, i.e. 135% - 60% = 75% damage, or is this an entirely seperate multiplier leading to 135% x (100% - 60%) = 54% damage.
Third enemy is even more unclear. Is this a 60% reduction from the original damage, or from the damage on the second enemy. So does it do the same as the second enemy (either 75% or 54% damage), or apply the same type of reduction a second time leading to either 75% - 60% = 15%, or 54% x (100% - 60%) = 21.6% damage.
As far as whether it's subtraction or multiplication is mostly just to sate my curiousity, but if the third hit is reduced by 60% twice, then I'm never going to spec it that way again because it's just too little damage to be worth anything.
Chain Overload Damage
Débuté par
Superelf62
, avril 20 2012 05:13
Retour en haut
#2
Posté 27 juin 2012 - 12:28
himegoto
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Giving you a bump cause I've been curious about this too.
#3
Posté 27 juin 2012 - 03:11
Nightmare137
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I believe it's reduced by the overall amount done after % multipliers. So any % multiplier would buff the chain damage as well. I could be wrong but this was how I understood it worked.
In short without any other% damage boosts to benefit it both chains would do approximately 118.8 damage each.
In short without any other% damage boosts to benefit it both chains would do approximately 118.8 damage each.
