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so... what's up with the "agents of the inquisition"?


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#1
AlmightyCarrot

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yeah... I completed the personal challenge yesterday right after they fixed the challenges bug thingy but I saw that I didn't get a star for "agents of the inquisition" so I thought "maybe the event has to end first or something weird like that" but now I log in after the update and I see that not only do I not have 4 stars as I should, there are no stars or a way to monitor that challenge whatsoever  :mellow:

 

so... what's going on exactly?



#2
Robbiesan

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if you haven't yet, check this thread.  Sounds like a lot of players were affected.  Going to check my challenges when I get home tonight.

 

http://forum.bioware...lenge-extended/



#3
AlmightyCarrot

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I guess I was just too lazy to look at all the comments...



#4
Robbiesan

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No worries.  For anyone else reading this thread, a new post about this issue has been posted by our pal Bill Buskell.

 

http://forum.bioware...es-please-read/



#5
Proto

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No worries.  For anyone else reading this thread, a new post about this issue has been posted by our pal Bill Buskell.

 

http://forum.bioware...es-please-read/

 

Blar must be insulted that you think he's Billy.



#6
DragonRacer

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Blar must be insulted that you think he's Billy.

 

Should we inform them that they're interchangeable now?



#7
Proto

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Should we inform them that they're interchangeable now?

 

I'll let you have the honors.


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#8
ParthianShotX

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Blarbilly.  Billar.  billblarry.  B2


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#9
Proto

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B2

 

Perfection.


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#10
DragonRacer

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I like Parthian's suggestion. "Blarry" also came to mind. Like the world's beardiest Voltron/gestalt Transformer.


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#11
Fiddzz

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im ok with this.


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#12
Robbiesan

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Doh!  Thanks for pointing that out Proto.

 

Hold on.  Isn't it Blair Brown and Billy Buskell or = B^4?


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#13
ParthianShotX

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No. B4 was taken back in time to help the Minbari.
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#14
Robbiesan

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No. B4 was taken back in time to help the Minbari.

 

Ok, fair enough.

 

How about B^2 + B^2?

 

or, B^1 + B^3

 

or, since Billy's math is, well-could be better, (B^6 - B^4) + B^2 * B^1.12^55409 / B^8?


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#15
Texasmotiv

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They are all one in the beard trinity.
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#16
ParthianShotX

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Ok, fair enough.

I totally did not expect you to pick up on that so fast.